Solutions
Solutions 1-4.
Based on the information given, we can come up with the following alternatives:
Possibility 1:
In either case the answers are the same:
1.
Miss West Bengal wore red. Option (b) is correct.2. Miss West Bengal was adjacent to Miss Andhra Pradesh and Miss Uttar Pradesh. Option (c) is correct.
3. Miss Andhra Pradeshwore the green saree. Option (c) is correct.
4. Miss Andhra Pradesh was the runner up as she wears green and sits next to Miss Maharashtra in both cases. Option (a) is correct.
5. Miss Uttar Pradesh was the winner. Option (c) is correct.
Reaction Tracker for Questions 6 to 10: This question seems to be quite confusing due to the reason that all the clues seem to be the same/similar in nature. While that might be true on the surface, there are a few distinctions in the ways the clues can be used— especially when we look at the clues in the correct order.
On combining clues (i) and clues (iii) we would get the following Table 1:
Note: We combine Clues (i) and (iii) because Clue (ii) is not usable at this stage, as it is what can be described as “a checking” clue, i.e. once we have multiple final figure possibilities in place, we use clues of the nature of clue (ii) and also clue (i) (Sacha was not the superman), to eliminate one of the possibilities.
Clue (iv) will give us Table 2:
Clue (v) would give us Table 3:
Clue (vi) would give us Table 4:
Costume Person Category best
From this point we need to focus on Sacha’s costume.
We would realise that Sacha cannot wear Superman (given clue (i)); Cannot wear joker (as joker is above Sacha according to Table 1) and cannot wear Lex Luthor because we cannot superimpose Table 4 on Table 1 by making Sacha correspond to Lex Luthor as it leads to the joker being the smartest (but Table 1 has joker as most efficient).This leaves us with 2 possibilities for Sacha’s costume—Wonderwoman or Batman.
Let us take a look at how possibility 1 rolls out:
For Sacha to be Wonderwoman we would need to merge Tables 1 and 2 to get Table 5 below:
To this we need to merge Table 3, which would give us Table 6 below:
There is only one way from this point that Table 4 can get merged into Table 6. That would give us:
That leaves us with a final solution as below.
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We can clearly see that this solution table contradicts clue (ii) - i.e. Billy was not the strongest.
Thus, we reject Possibility 1 and move to a possibility which would give us that Sacha must be Batman. In this case the thinking pattern would go as follows:
CombiningTable 3 with Table 1:
To this we merge Table 3 and get:
To this we merge Table 4 and get:
Scariest
This leaves us with the task of placing the remaining values in each column.
When we do this we get:
This solution does not contradict any of the basic clues given in the question. Hence, the answers are:
6. Billy ranked fifth. Option (a)
7. Billy got the scariest costume. Option (a)
8. Sacha’s costume is Batman. Option (b) is correct.
9. Option (c) is the correct order.
10. Only (IV) and (V) are not properly matched. Hence, Option (a) is correct. Reaction Tracker to Questions 11-15: There are essentially two logical forks in this question:
The first one comes from Clue (i), according to which the highest total of vest number and time must be 13 (as the square is 169).
This could mean two scenarios:
Vest number 7 with time=6; or vest number 6 with time=7.
The two scenarios can be shown as:
Inside these two scenarios we need to merge the other three way fork:
The square of the least total of vest number and rank is 16 and occurs only once. It gives us 3 scenarios on the surface:
However in this scenario we can reject Vest 3 ranking 1 because then the second ranker’s vest number would exceed the winner’s vest number (Clue (iv))—as we cannot put the 2nd rank for either 1 or 2 as the total of 4 is the least sum and occurs only once.
This leaves us with 4 principal situations 1A, IB, 2A and 2B. Let us evaluate each of these separately:
In the above situation, the total of vest number + rank has to occur thrice. There are only 3 places where this can actually occur given the possibilities listed above. These are 2- 7; 4-5 and 5-4. Hence, the following conclusions can be made:
3-2 and 6-1 get automatically selected.
As for the vest number 3, only rank possibility left is 2nd rank and after than rank 1 must go to vest number 6.If we go for a similar analysis with the other possibilities you can see that they do not work out. For instance in Possibility IB, if we put down what is possible to be placed against vest numbers 1 and 3 respectively we get the following figure.
From this point we know that there have to be exactly 3 totals of 9, which can only be achieved by matching 4-5; 5-4 and 6-3. Then, 3rd vest must be 7th rank but that leaves us with no rank possibility for vest 1 and also rank 1 not getting allotted anywhere. Thus, this possibility does not exist.
Similarly we can reject possibilities 2A and 2B:
In the above table we need three 9s. There are 4 possibilities for the sum of vest number and rank to be 9. These are 3-6, 4-5, 5-4 and 7-2. Only 3 of these 4 have to make up 9, hence we will have to leave out one of the 4. If we leave out 3-6, 4-5 or 5-4 then vest number 7 must take Position 2 (runner up). This will contradict Clue (iv) as the winner’s vest number > the runner-ups vest number. If we leave out 7-2 and place 3-6, 4-5 and 5-4 there will be no place to put rank 2. Thus, this possibility gets rejected. Possibility 2B also gets rejected as follows:
In the table above, there are only 3 cases of total of vest number + rank = 9. Thus, the table should become:
Thus, this possibilityis also rejected.
The answers are:
11. Vest number 6. Option (b)
12. Vest number 3. Option (d)
13. Vest number 2. Option (d)
14. Vest number 2. Option (b)
15. Vest number 7. Option (a)
16. Ben gets a chance to eliminate (Clue a); Frank gets a chance to eliminate (Clue e); Devon gets a chance to eliminate (Clue h); Only Charlie does not get a chance to eliminate someone. Option (b) is correct.
17. Frank and Ian satisfy the condition of not being in the top four in any event. Of them Ian would not get eliminated (Clue i); Frank would get eliminated (Clue d). Option (d)
18. Garrywho is getting eliminated by Clue f would not be eliminated due to this Clue.
19. Clue b does not have any usage in this question.
20. John is getting eliminated due to Clue h, which pertains to 9th rank in the event D. Also, Devon is getting eliminated due to maximum number of last ranks, which would no longer be true. Thus, Option (d) is correct.
21. If G is fifth, then A and B must be ranked 6th and 7th respectively This can only happen if D scores the highest (as, if C is highest, then E must be 7th. Option (a)
22. The first three options are not feasible. Option (d) is the only thing that can be true.
23. Option (d) is possible.
24. The ordering in terms of sweetness would be L>G>R>C andpβi∕zαs, (P) have to be
greater than chamchams (C). Thus, clearly the third statement is true.
25. Both A and C weigh more than B. However, it is not certain whether C weighs the most. Thus, we choose Option (c).
26. Uncertain. Option (c).
27. We will get from the first two statements T>H>C>F. Thus Statement 3 is false if the first two statements are true.
28. False, as we get A>B>C and hence C>A is definitely false. Option (b)
Solutions to 29 to 32:
The solution table would be:
Hence, the answers are:
29. Nagpur (Option d)
30. Aurangabad (Option a)
31. Ahmednagar ranked fourth and got 54 inches of rain. (Option b).
32. Mumbai is located in a valley (Option c).